Round Robin Tournament Scheduling
Schedules - You must register to Post and Download => Requests => Topic started by: CentralBlue on January 27, 2009, 10:34:37 PM
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The Challenge: 10 teams max of 16 rounds in a season. 9 rounds = everybody playing each other once.
Goal: Every team plays every other an equal number of times (3) over the coarse of two seasons.
Last season we had 13 rounds every team played the others once and 4 of the teams 2 twice.
So this season there should be 14 rounds as every team plays the others once and the remaining 5 teams twice
I can not seam to get the schedule to work. Kind of stumped.
here is what I have.
So - here are the teams that need to play each other twice this season in order for every team to have played each other 3 times over the two years.
10 plays - 2,4,6,8,9
9 plays - 1,3,5,7,10
8 plays - 2,4,6,7,10
7 plays - 1,3,5,8,9
6 plays - 2,4,7,8,10
5 plays - 1,3,6,7,9
4 plays - 2,3,6,8,10
3 plays - 1,4,5,7,9
2 plays - 1,4,6,8,10
1 plays - 2,3,5,7,9
Can it be done??
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Would you please post the schedule that you played for the first 13 rounds.
I am not sure the list of matches to be played twice is correct. Shouldn't it be symmetrical? For example it says that team 5 should play 6, but team 6 does not play 5.
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You are correct it was an typo, probably occur when I copied from the piece of paper I had written it on. Actually figured the problem out. the solution is.
Round 10 2-4 8-6 1-3 7-5 9-0
Round 11 6-2 4-0 5-1 3-9 8-7
Round 12 2-0 4-8 1-9 3-7 5-6
Round 13 8-2 0-6 7-1 9-5 4-3
Round 14 6-4 0-8 5-3 9-7 1-2
Thanks