I am not able to find an ideal solution to this problem, and think the only option is to compromise on the pairwise balance. I have not checked in detail, but in the schedule below I think each player gets about 15 or 16 different opponents rather than the 18 different opponents that you were hoping for.
Machine 1 Machine 2 Machine 3 Machine 4 Machine 5 Machine 6
R1 ( 3 17 9 15) (23 19 1 14) (13 12 24 8) ( 5 18 11 22) (20 7 16 4) ( 6 2 21 10)
R2 ( 1 18 7 13) (24 20 2 15) (14 10 22 9) ( 6 16 12 23) (21 8 17 5) ( 4 3 19 11)
R3 ( 2 16 8 14) (22 21 3 13) (15 11 23 7) ( 4 17 10 24) (19 9 18 6) ( 5 1 20 12)
R4 (21 11 6 24) ( 4 8 18 10) (19 2 5 17) (20 9 1 13) ( 3 23 12 14) (16 7 22 15)
R5 (19 12 4 22) ( 5 9 16 11) (20 3 6 18) (21 7 2 14) ( 1 24 10 15) (17 8 23 13)
R6 (20 10 5 23) ( 6 7 17 12) (21 1 4 16) (19 8 3 15) ( 2 22 11 13) (18 9 24 14)
Hope that helps.