Round Robin Tournament Scheduling
Schedules - You must register to Post and Download => Requests => Topic started by: Innesw20 on February 20, 2025, 05:58:32 AM
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In the game of lawn bowls, if there are only 8 teams in a competition there would frequently be more rinks available (the standard green has eight) than are required to play each round (4).
The mathematicians have shown that there does not exist a PBTD for 8 teams and 4 venues.
I was wondering whether a PBTB-equivalent for 8 teams could be constructed where the number of venues is 5 instead of 4? If not, would 6 venues allow it? Or is it just not mathematically possible? This is essentially easing the restriction on the number of venues that applies in the standard definition of PBTDs.
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The PBTD might not be necessary. Could you use the regular balanced schedule instead. Go here (https://www.devenezia.com/downloads/round-robin/rounds.php) and enter 8 items and 'balanced'.
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Afraid not - it does need to be partitioned: a team at a venue at most once in rounds 1-4 and at most once in rounds 4-7.
I imagine it would look something like this, if it can work for 5 venues (rounds in rows, venues in cols):
( ) (1 x) (x x) (x x) (x x)
(x x) (x x) ( ) (x x) (1 x)
(x x) ( ) (1 x) (x x) (x x)
(1 x) (x x) (x x) (x x) ( )
(x x) (x x) (1 x) ( ) (x x)
(x x) ( ) (x x) (x x) (1 x)
( ) (x x) (x x) (1 x) (x x)
Ideally each team should play on each venue at least once in the competition, but that may be asking too much.
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The more venues there are, the easier things get. With 6 venues you can have:
(H A) (---) (F G) (B C) (---) (D E)
(---) (H B) (---) (F E) (D G) (A C)
(E G) (D F) (H C) (---) (A B) (---)
(---) (A E) (---) (H D) (F C) (B G)
(F B) (C G) (D A) (---) (H E) (---)
(D C) (---) (B E) (A G) (---) (H F)
which leaves the following 4 pairings to be played in the final round.
(A F) (B D) (C E) (G H)
If you have 7 venues, then there is the Room Square (https://en.wikipedia.org/wiki/Room_square).
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Thanks Ian, they solve my problem.