7 players, tripple play

[Bakdal]

Hi there.

I am sure it's simple, but still:

A schedule for seven players, playing seven games in tripples. That should add up to all players playing together two times, and against each other three times.

Could you make a scheme?

Thanks in advance,

Klaus

[Ian Wakeling]

Hi Klaus,

There is a simple cyclic solution to this, so given the first round, the other rounds are formed just by rotating through the players in order.  For example:

                  Bye
(1 2 4) v (3 5 6)  7
(2 3 5) v (4 6 7)  1
(3 4 6) v (5 7 1)  2
(4 5 7) v (6 1 2)  3
(5 6 1) v (7 2 3)  4
(6 7 2) v (1 3 4)  5
(7 1 3) v (2 4 5)  6

Ian