Round Robin Tournament Scheduling

Co-ed Volleyball

yourmommag · 3 · 3047

yourmommag

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on: March 22, 2022, 06:24:15 PM
Hi -
Sorry, having trouble navigating through the site to see if it's already been answered. I've seen different answers, but they seemed to have an unending number of courts :D

This is for KOB (king of the beach) volleyball.  It's also seen often in tennis.  Where a co-ed couple plays with a different co-ed couple each round and against 4 others (who are also being coupled up).  Would be nice, if you didn't always play against one person.

10 boys
10 girls
2 courts
(4 people have a bye, every game)
Teams are made of 2 girls 2 boys
Would like a couple different scenarios
1) Set Boy girl partners, playing with different partners every round. (This would look like T1 T2 v T3 T4, court 2 T5 T6 v T7 T8 )
2) random combinations of boys and girls playing with different boy girl every round. (Ex. b1 b3 g2 g4 v b2 b4 g1 g3)

Thank you much in advance!
« Last Edit: March 23, 2022, 11:52:11 AM by Ian Wakeling »


Ian Wakeling

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Reply #1 on: March 23, 2022, 12:06:38 PM
I have moved your post into this new topic and given it a suitable title.

Concerning your question, I think scenario #1 is a much easier proposition.  Once the boys and girls are assigned to 10 pairs, then you are simply looking for a doubles schedule for 10 participants.  There are some schedules linked to in this recent thread that you might find useful.

Scenario #2 is really hard and a balanced schedule is unlikely. There is the issue that a player has different numbers of same sex and opposite sex partners/opponents - there are 9 of the former, and 10 of the latter in your example.


Ian Wakeling

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Reply #2 on: March 23, 2022, 03:15:45 PM
I was thinking some more about scenario #2 - and if there were only 8 boys and 8 girls, then you could possibly play this 7 round schedule:

 (b5 b6 g8 g7 : b3 b4 g2 g1) (b1 b2 g4 g3 : b7 b8 g6 g5)
 (b6 b8 g4 g2 : b1 b3 g7 g5) (b5 b7 g3 g1 : b2 b4 g8 g6)
 (b1 b4 g6 g7 : b2 b3 g5 g8) (b5 b8 g2 g3 : b6 b7 g1 g4)
 (b4 b8 g5 g1 : b3 b7 g6 g2) (b2 b6 g7 g3 : b1 b5 g8 g4)
 (b2 b5 g6 g1 : b3 b8 g7 g4) (b1 b6 g5 g2 : b4 b7 g8 g3)
 (b1 b7 g2 g8 : b3 b5 g4 g6) (b4 b6 g3 g5 : b2 b8 g1 g7)
 (b2 b7 g4 g5 : b3 b6 g1 g8) (b1 b8 g3 g6 : b4 b5 g2 g7)

The 8 pairs (b1 g1), (b2 g2), etc. never play together, but otherwise everything is good, a player:
partners the same sex players once
partners the other opposite sex players twice
opposes all other players twice

Unfortunately I see no way to do anything similar for 10 boy and 10 girls, it is possible it might work with 12 boys and 12 girls and 3 simultaneous games per round.