I'm trying to set up a schedule for a 7 weeks for a horseshoe league. Each player will be teamed up with a different player every week (two man team). Each team will play a different team each week. Each player will play a different player every week. And each player will only have the same player as a partner, opponent, and opponents partner only once. 8 total players.
I know there has to be a way to figure this out easily, but it has eluded me thus far. Thanks in advance for any advice you can offer,
Mike
Thursday, June 2 2005, 07:24 pm
OconomowocThe solution could not elude Mike. 19 days later he graciously posted his solution as:
1+4 vs 6+8 (1v6) (4v8) 3+5 vs 2+7 (5v7) (2v3)
2+8 vs 6+7 (2v6) (7v8) 1+5 vs 3+4 (1v3) (4v5)
2+6 vs 1+3 (3v6) (1v2) 4+5 vs 7+8 (5v8) (4v7)
4+7 vs 3+6 (4v6) (3v7) 1+2 vs 5+8 (1v8) (2v5)
4+6 vs 2+5 (5v6) (2v4) 1+8 vs 3+7 (1v7) (3v8)
1+6 vs 5+7 (6v7) (1v5) 4+8 vs 2+3 (3v4) (2v8)
5+6 vs 3+8 (3v5) (6v8) 1+7 vs 2+4 (1v4) (2v7)
Thanks Mike!
