Round Robin Tournament Scheduling

12 players, 4 rounds,

EWS · 4 · 8947

EWS

  • Newbie
  • *
    • Posts: 2
on: April 02, 2011, 03:51:37 PM
Have read through quite a number of posts and realize that to get perfection we need to take two more days off. Alas not happening!

We are 12 and ideally everyone wants to play with evryone at least once in foursomes. Whats the best we can do?


Ian Wakeling

  • Forum Moderator
  • God Member
  • *****
    • Posts: 1140
Reply #1 on: April 04, 2011, 07:32:34 AM
There will be 12 pairs of players who never play together.  Also there will be 18 pairs who play together twice.  You could take advantage of this 2nd feature by assigning players into three ability groups, then each of the repeated matches would be with someone of equal ability.

 ( 9  7  6  5)  (1  8  4  2)  (3 11 12 10)
 (10  8  7  6)  (2  5  1  3)  (4 12  9 11)
 (11  5  8  7)  (3  6  2  4)  (1  9 10 12)
 (12  6  5  8)  (4  7  3  1)  (2 10 11  9)


Within the player groups (1 2 3 4) (5 6 7 8) (9 10 11 12),  all pairs play together twice.

The following pairs don't play together:
    1   6
    1  11
    2   7
    2  12
    3   8
    3   9
    4   5
    4  10
    5  10
    6  11
    7  12
    8   9
« Last Edit: April 14, 2011, 07:15:45 AM by admin »


EWS

  • Newbie
  • *
    • Posts: 2
Reply #2 on: April 20, 2011, 10:59:19 AM
Thanks - I ended up using a threesome lay out that worked great until my host advised that we are now 14 people in the group!

Do you have any examples of  say 2 4somes and 2 3somes mixing it up to maximize face time over 6 or 7 rounds of golf?

Thanks


Ian Wakeling

  • Forum Moderator
  • God Member
  • *****
    • Posts: 1140
Reply #3 on: April 21, 2011, 10:19:56 AM
I think the following will work, with players playing 3 games in threesomes and 4 games in foursomes.

(3 7 11 1) ( 8 13 6 12) (10 5 2) ( 9 14 4)
(4 1 12 2) ( 9 14 7 13) (11 6 3) (10  8 5)
(5 2 13 3) (10  8 1 14) (12 7 4) (11  9 6)
(6 3 14 4) (11  9 2  8) (13 1 5) (12 10 7)
(7 4  8 5) (12 10 3  9) (14 2 6) (13 11 1)
(1 5  9 6) (13 11 4 10) ( 8 3 7) (14 12 2)
(2 6 10 7) (14 12 5 11) ( 9 4 1) ( 8 13 3)


All pairs playing together either once or twice.
« Last Edit: April 21, 2011, 10:20:24 AM by Ian »