Court Balanced schedule with counted game.

[hudi1]

Hello,

situation:

we have 3 group of 10 which play games. Now five people promoting to final group A. So this group have 15 players, 5 from group 1, five from group 2 etc. Task is how to create schedule where games are counted from basic group. What does it mean ? Player 1 from group 1 already played games against players 2-5 from group 1 and so on so we want to miss this game from schedule. For even groups it is really easy. Problem is how to created it for odd number of groups. Unbalanced solution is that first half from group 1 play with first half from group 2. Second half of group 2 play with second half from group 3 and first half of group play with second half from group 1. But this solution is isn't good for me. Any ideas ?

[Ian Wakeling]

If I understand correctly, then I think there will be 75 games to play, but how do you want to play them?   In rounds of 7 simultaneous games?

[hudi1]

yes in each round there will be 7 games and one player have pause

[Ian Wakeling]

I have thought about this, but unfortunately I can't see any solution.  The only way I can see is to make three bipartite tournaments between the groups of 5, I think this is the same as you are suggesting above, which would give 15 rounds of 5 games each.  There is almost certainly a solution with fewer rounds, but the only way forward that I can see, would be to write a computer search program specifically for this problem.