Balanced 10 player golf schedule

[HGGolf]

10 players, 9 weeks
Play each player once
Evenly distributed times in twosome (I realize 2 players will only have this once, 8 players twice)
Evenly distributed times in foursome with each player.

Thank you.

[Ian Wakeling]

I think a regular balanced round-robin will give you what you want:

( 1  6) ( 2  7) ( 3  8) ( 4  9) ( 5 10)
( 2  5) ( 3  1) ( 4  7) (10  8) ( 6  9)
( 3  4) ( 9 10) ( 5  1) ( 6  7) ( 2  8)
( 2 10) ( 8  6) ( 9  7) ( 5  3) ( 1  4)
( 3  9) ( 4  5) (10  6) ( 1  2) ( 7  8)
( 7 10) ( 3  6) ( 4  2) ( 5  8) ( 1  9)
( 8  9) ( 4 10) ( 5  6) ( 1  7) ( 2  3)
( 7  5) ( 8  1) ( 9  2) (10  3) ( 6  4)
( 8  4) ( 9  5) (10  1) ( 6  2) ( 7  3)

simply group columns 1 & 2,  and columns 3 & 4 into foursomes, which leaves column 5 as the twosome.  Players 5 & 10 are the 2 players who play just once in twosomes.

[HGGolf]

Thank you for this. But just looking at player number one, he is in a foursome with one player 5 times, 3 players 4 times, 1 player 2 times, and 4 players just once. I'm looking for a little more even distributions of being in foursomes together.

[HGGolf]

Is it possible to distribute foursomes more evenly and maintain a balanced schedule & balanced twosomes? Thanks.