8 men 8 woman, Rotating Partner Mixed Round Robin

[Philly617]

I'm new to this site but am trying to figure out schedule for below format.

- 8 men
- 8 women
- Each person plays with every mixed partner which means 8 games
- playing on 4 courts
- How do I best randomize games so each person plays against everyone else and not playing the same person 3 or 4 times

[Ian Wakeling]

See here for a similar question.

and consider replies #1 or #8 here for 7 or 9 round schedules.  The first is spouse avoiding so there is one other opposite sex player who you never meet.

[Philly617]

Ian, I did see that post, #8 as I don't have any situation where we are avoiding a spouse.

Was wondering why there were 9 rounds in that scenario.

With 8 men and 8 women.  I'm looking for 8 round scenario where each male plays with each female once?  Is that covered in your 9 rounds scenario and one of the round is duplicative and I just need to delete it?

Appreciate your help.

[Ian Wakeling]

This is the best schedule that I have for 8 rounds:

(m06 f08 v m02 f03) (m01 f05 v m04 f06) (m03 f07 v m05 f02) (m08 f01 v m07 f04)
(m01 f08 v m07 f01) (m08 f05 v m05 f03) (m03 f02 v m06 f04) (m02 f06 v m04 f07)
(m02 f05 v m08 f02) (m04 f01 v m05 f04) (m07 f07 v m06 f03) (m01 f06 v m03 f08)
(m04 f03 v m01 f02) (m03 f05 v m07 f08) (m05 f01 v m06 f06) (m02 f07 v m08 f04)
(m08 f03 v m03 f06) (m07 f05 v m06 f07) (m04 f04 v m05 f08) (m02 f02 v m01 f01)
(m05 f07 v m01 f03) (m04 f05 v m03 f01) (m02 f04 v m07 f06) (m08 f08 v m06 f02)
(m07 f02 v m05 f06) (m04 f08 v m08 f07) (m03 f03 v m02 f01) (m01 f04 v m06 f05)
(m01 f07 v m03 f04) (m04 f02 v m07 f03) (m05 f05 v m02 f08) (m08 f06 v m06 f01)

It does contain all male/female partnerships exactly once, however the opposition pairings are not optimal.  In particular the following four pairs never oppose (m1 m8) (m4 m6) (f1 f7) (f3 f4).  Hope that helps.