Golf, 10 players, 3 rounds, minimize duplicates

[teetime]

Great site!

Ten golfers will play three rounds. Each round will have two threesomes and one foursome. I want to minimize duplicate pairings. Thanks.

Jerry

[Ian Wakeling]

Jerry,

I believe that 3 is the minimum number of duplicate pairings.  To achieve this, the duplicates must all occur in the foursomes.  So this does make for a somewhat unfair schedule as one player is always in the foursome and three players are always in the threesomes:

(1 2 3 5)   (4 8 9)   (6 7 10)
(1 2 4 6)   (3 8 10) (5 7 9)
(1 3 4 7)   (2 9 10)  (5 6 8)

Ian.

[teetime]

Ian, this is PERFECT for our needs. With your solution, every player gets to play with either 6 or 7 different golfers during the three day outing. Thanks for your quick response.

Jerry