Round Robin Tournament Scheduling

10 golfers 7 rounds

xxyyzz · 4 · 6964

xxyyzz

  • Newbie
  • *
    • Posts: 2
on: February 15, 2013, 10:27:31 AM
How can I schedule 10 golfers over 7 rounds, so everyone is with everyone else the same number of times.

The configuration can be 4 4 2  or 4 3 3 which ever works out better


Ian Wakeling

  • Forum Moderator
  • God Member
  • *****
    • Posts: 1140
Reply #1 on: February 16, 2013, 05:31:13 AM
I think 4 3 3 is the best format.  For example:

 (  1  4  3  7) (9  8  6)  (5  2 10)
 (  6  9  2  4) (1  5  3)  (8  7 10)
 (  4  5  8 10) (6  2  1)  (3  9  7)
 (  6  4 10  3) (2  8  1)  (7  5  9)
 ( 10  9  2  3) (8  1  4)  (6  5  7)
 (  7 10  6  1) (3  2  8)  (9  4  5)
 (  5  6  8  3) (4  7  2)  (1  9 10)

Above players  3,4,6 & 10 have 4 foursomes and 3 threesomes (all 9 opponents exactly twice each), while the other 6 players have 2 foursomes and 5 threesomes (7 opponents twice each and 2 opponents only once).

Hope that helps.


xxyyzz

  • Newbie
  • *
    • Posts: 2
Reply #2 on: February 17, 2013, 09:39:54 AM
Thnaks.

I just found out that one of rounds is not happening.. so we r only doing 6 rounds.. does that change things?


Ian Wakeling

  • Forum Moderator
  • God Member
  • *****
    • Posts: 1140
Reply #3 on: February 18, 2013, 03:43:06 AM
The best solution for 6 rounds is to have one golfer (player 10) who always plays in the foursome and who has all 9 opponents exactly twice.

Below players 1 to 9 all have exactly 2 games in foursomes and 4 games in threesomes with all opponents either once or twice (4 of them once and 5 of them twice).

  (10  9  5  6)  (3  4  2)  (7  8  1)
  (10  7  6  4)  (1  5  3)  (8  9  2)
  (10  8  4  5)  (2  6  1)  (9  7  3)
  (10  8  3  2)  (4  1  6)  (9  7  5)
  (10  9  1  3)  (5  2  4)  (7  8  6)
  (10  7  2  1)  (6  3  5)  (8  9  4)