Hi Shaun,If I understand correctly then the situation can not be even, some pairs of players will meet 3 times, while other pairs will meet 4 times. For example:(4 2 8 3) (1 6 7 5)(6 8 3 7) (2 4 5 1)(3 6 5 4) (7 2 1 8)(2 5 8 6) (7 3 4 1)(3 1 2 6) (5 8 7 4)(6 1 4 5) (8 3 2 7)(5 7 3 2) (1 4 6 8)(4 7 6 2) (8 5 1 3)Does that work for you?Ian.