I think the schedule below will work out OK.
(11 17 8 15) ( 6 4 12 5) ( 1 2 7) (3 13 14) (16 9 10)
(16 1 12 3) ( 8 6 10 13) (14 11 9) (4 17 7) ( 5 2 15)
( 4 14 10 2) (15 3 7 9) (17 12 13) (5 16 8) (11 6 1)
Above no pair of players are together more than once. Players 3,4,6,8,10,12 & 15 have two fourballs and 8 different opponents, while the other players have one fourball and 7 different opponents. Hope that helps.