I found this site to be helpful, but I am not a methematical genius to work out my specific problem. I have the round robins figured out for most of my options except 10 people. We want to use the Whist is that out of the 10, each person is paired with another exactly once, but plays against all other persons exacly twice. This is for Euchre, but bould be used for Bridge and other games. My calculations conclude that one pairing is left over and would have to play a dummy hand--against 2 persons drawn randomly whose score would not count. Any help out there??
