Gavel,
Yes, 6 byes in a similar format is possible, for example:
(1 8) (4 16) (20 12) (7 10) (3 19) (6 11) (18 22) (14 15) (2 9 5 17 21 13)
(2 9) (5 17) (21 13) (8 11) (4 20) (7 12) (19 1) (15 16) (3 10 6 18 22 14)
(3 10) (6 18) (22 14) (9 12) (5 21) (8 13) (20 2) (16 17) (4 11 7 19 1 15)
(4 11) (7 19) (1 15) (10 13) (6 22) (9 14) (21 3) (17 18) (5 12 8 20 2 16)
(5 12) (8 20) (2 16) (11 14) (7 1) (10 15) (22 4) (18 19) (6 13 9 21 3 17)
(6 13) (9 21) (3 17) (12 15) (8 2) (11 16) (1 5) (19 20) (7 14 10 22 4 18)
(7 14) (10 22) (4 18) (13 16) (9 3) (12 17) (2 6) (20 21) (8 15 11 1 5 19)
(8 15) (11 1) (5 19) (14 17) (10 4) (13 18) (3 7) (21 22) (9 16 12 2 6 20)
(9 16) (12 2) (6 20) (15 18) (11 5) (14 19) (4 8) (22 1) (10 17 13 3 7 21)
(10 17) (13 3) (7 21) (16 19) (12 6) (15 20) (5 9) (1 2) (11 18 14 4 8 22)
(11 18) (14 4) (8 22) (17 20) (13 7) (16 21) (6 10) (2 3) (12 19 15 5 9 1)
(12 19) (15 5) (9 1) (18 21) (14 8) (17 22) (7 11) (3 4) (13 20 16 6 10 2)
(13 20) (16 6) (10 2) (19 22) (15 9) (18 1) (8 12) (4 5) (14 21 17 7 11 3)
(14 21) (17 7) (11 3) (20 1) (16 10) (19 2) (9 13) (5 6) (15 22 18 8 12 4)
(15 22) (18 8) (12 4) (21 2) (17 11) (20 3) (10 14) (6 7) (16 1 19 9 13 5)
(16 1) (19 9) (13 5) (22 3) (18 12) (21 4) (11 15) (7 8) (17 2 20 10 14 6)
(17 2) (20 10) (14 6) (1 4) (19 13) (22 5) (12 16) (8 9) (18 3 21 11 15 7)
(18 3) (21 11) (15 7) (2 5) (20 14) (1 6) (13 17) (9 10) (19 4 22 12 16 8)
(19 4) (22 12) (16 8) (3 6) (21 15) (2 7) (14 18) (10 11) (20 5 1 13 17 9)
(20 5) (1 13) (17 9) (4 7) (22 16) (3 8) (15 19) (11 12) (21 6 2 14 18 10)
(21 6) (2 14) (18 10) (5 8) (1 17) (4 9) (16 20) (12 13) (22 7 3 15 19 11)
(22 7) (3 15) (19 11) (6 9) (2 18) (5 10) (17 21) (13 14) (1 8 4 16 20 12)
With the extra byes, there are now 55 possible matches that are not played. Although I have used a computer to generate these schedules, they were essentially constructed by hand on an Excel spreadsheet. The cyclic property means that each column contains distinct subsets of all possible matches, all with the same difference. So the problem is reduced to finding round one as the rest of the scehdule can be generated from it.
Are you looking for 21 round solutions for the 21 team scenario?
Regards,
Ian.
(from Norfolk in England)